Optimal. Leaf size=93 \[ -\frac {a 2^{\frac {p}{2}+\frac {3}{2}} (\sin (c+d x)+1)^{\frac {1}{2} (-p-1)} (e \cos (c+d x))^{p+1} \, _2F_1\left (\frac {1}{2} (-p-1),\frac {p+1}{2};\frac {p+3}{2};\frac {1}{2} (1-\sin (c+d x))\right )}{d e (p+1)} \]
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Rubi [A] time = 0.06, antiderivative size = 93, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {2688, 69} \[ -\frac {a 2^{\frac {p}{2}+\frac {3}{2}} (\sin (c+d x)+1)^{\frac {1}{2} (-p-1)} (e \cos (c+d x))^{p+1} \, _2F_1\left (\frac {1}{2} (-p-1),\frac {p+1}{2};\frac {p+3}{2};\frac {1}{2} (1-\sin (c+d x))\right )}{d e (p+1)} \]
Antiderivative was successfully verified.
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Rule 69
Rule 2688
Rubi steps
\begin {align*} \int (e \cos (c+d x))^p (a+a \sin (c+d x)) \, dx &=\frac {\left (a (e \cos (c+d x))^{1+p} (1-\sin (c+d x))^{\frac {1}{2} (-1-p)} (1+\sin (c+d x))^{\frac {1}{2} (-1-p)}\right ) \operatorname {Subst}\left (\int (1-x)^{\frac {1}{2} (-1+p)} (1+x)^{1+\frac {1}{2} (-1+p)} \, dx,x,\sin (c+d x)\right )}{d e}\\ &=-\frac {2^{\frac {3}{2}+\frac {p}{2}} a (e \cos (c+d x))^{1+p} \, _2F_1\left (\frac {1}{2} (-1-p),\frac {1+p}{2};\frac {3+p}{2};\frac {1}{2} (1-\sin (c+d x))\right ) (1+\sin (c+d x))^{\frac {1}{2} (-1-p)}}{d e (1+p)}\\ \end {align*}
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Mathematica [C] time = 1.40, size = 245, normalized size = 2.63 \[ -\frac {i a 2^{-p-1} \left (e^{-i (c+d x)} \left (1+e^{2 i (c+d x)}\right )\right )^{p+1} (\sin (c+d x)+1) \left ((p+1) e^{i (c+d x)} \left (i p e^{i (c+d x)} \, _2F_1\left (1,\frac {p+3}{2};\frac {3-p}{2};-e^{2 i (c+d x)}\right )-2 (p-1) \, _2F_1\left (1,\frac {p+2}{2};1-\frac {p}{2};-e^{2 i (c+d x)}\right )\right )-i (p-1) p \, _2F_1\left (1,\frac {p+1}{2};\frac {1-p}{2};-e^{2 i (c+d x)}\right )\right ) \cos ^{-p}(c+d x) (e \cos (c+d x))^p}{d (p-1) p (p+1) \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )^2} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.50, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (a \sin \left (d x + c\right ) + a\right )} \left (e \cos \left (d x + c\right )\right )^{p}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (a \sin \left (d x + c\right ) + a\right )} \left (e \cos \left (d x + c\right )\right )^{p}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 1.49, size = 0, normalized size = 0.00 \[ \int \left (e \cos \left (d x +c \right )\right )^{p} \left (a +a \sin \left (d x +c \right )\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (a \sin \left (d x + c\right ) + a\right )} \left (e \cos \left (d x + c\right )\right )^{p}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int {\left (e\,\cos \left (c+d\,x\right )\right )}^p\,\left (a+a\,\sin \left (c+d\,x\right )\right ) \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ a \left (\int \left (e \cos {\left (c + d x \right )}\right )^{p}\, dx + \int \left (e \cos {\left (c + d x \right )}\right )^{p} \sin {\left (c + d x \right )}\, dx\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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